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- Timestamp:
-
Nov 21, 2010, 5:24:56 PM (14 years ago)
- Author:
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Víctor de Buen Remiro
- Comment:
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Efectivamente, puede hacer cualquier cosa menos caerse.
Legend:
- Unmodified
- Added
- Removed
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Property
Status
changed from
new
to
accepted
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initial
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v1
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|
3 | 3 | si se compila |
4 | 4 | |
| 5 | {{{ |
5 | 6 | NameBlock A1 = [[ |
6 | 7 | Real a = 1, |
… |
… |
|
13 | 14 | Set AB = [[A1, A2]]; |
14 | 15 | Set C = Unique(AB); |
| 16 | }}} |
15 | 17 | |
16 | 18 | la función Unique funciona sin problemas, el set C contiene un elemento y se entiende que la comparación funciona con NameBlocks. Sin embargo si diferenciamos los NameBlocks... |
17 | 19 | |
18 | | |
| 20 | {{{ |
19 | 21 | NameBlock A1 = [[ |
20 | 22 | Real a = 1, |
… |
… |
|
28 | 30 | Set AB = [[A1, A2]]; |
29 | 31 | Set C = Unique(AB); |
| 32 | }}} |
30 | 33 | |
31 | 34 | ... tol tiene un error fatal y se cierra! |